Voltage & Current

Last few weeks were exceedingly hard, student life is a pain and life of a physics student is barely a life at all! But we push on! There is plenty of time and I am confident that it will be a great success. Research is being continued in that little free time I have, facts get studied, brains get fried. One bit at a time.

The voltages required to achieve fusion with deuterium are between 30kV and 35kV, which will mean getting a fat transformer. Demonstration fusor required around 10kV of potential however that means no deuterium and no fun! Not good in my books. However the transformer would have to be a lot smaller…

The good news is that current required should be very small, between 15mA and 20mA, and since current is the one that kills you, my butt feels safe for now. All the work is being done by the potential due to voltage gradient of course, and too much current would cause the internal grid to overheat and melt.

Speaking of the grid, the device will need a spherical tungsten grid, which must be ‘negative hot’ meaning the high voltage will be applied to it, whereas the shell around it, which in this case will be the metal vacuum containment vessel will be positively grounded. Spherical grid will be providing roughly equal potential gradient in all directions, and hence the amount of force acting on each deuteron, increasing the likelihood of a collision resulting in fusion! Of course the geometry of the shell must be taken into account but I simply won’t do it at this stage, because most containment vessels are cylindrical, and putting the interaction of sphere and cylinder on paper is not the kind of thing I wanna do right now… Perhaps it will be worth calculating the energy given to each deuteron in our fusor once we get the components together.

I also saw someone make a cylindrical grid, or like a can grid, so that fusion would take place inside said can. It’s interesting, but just doesn’t seem to be a good idea to me bcause the amount of degrees of freedom of deuterons’ movement directions is drastically decreased with that set up! And that means less chance of a collision resulting is successful fusion.

So with the electrical part, I foresee great difficulty in obtaining a suitable transformer, perhaps from an x-ray machine… However there are a million places to look before losing hope and practical business is not my concern right now.

So this covers the 3 key conditions for a fusor to operate, voltage, current and pressure. Voltage – high. Pressure and current – very small. Finding components – hard.